Q(t)=1/2(0.85^t)

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Solution for Q(t)=1/2(0.85^t) equation: 



(Q)=1/2(0.85^Q)

We move all terms to the left:

(Q)-(1/2(0.85^Q))=0



Domain of the equation: 2(0.85^Q))!=0

Q∈R



We multiply all the terms by the denominator


Q*2(0.85^Q))-(1=0

Wy multiply elements

2Q^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Q=\frac{-b}{2a}=\frac{0}{4}=0$

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